Matematika

Pertanyaan

nilai tan kuadrat phi/6- sec kuadrat phi/4 + cosec kuadrat 5 phi/6

1 Jawaban

  • Tan²π/6 = Tan²180/6= sin²30 / cos²30= (½)² / (½√3)²= 1 / 3

    Sec²180/4= 1/cos²45 = 1/(½√2)²=1/8

    Cosec5(180)/6 = 1/sin150° = 1/sin(180°-30°)= 1/sin30= 1/½= 2

    jadi
    ⅓ - 1/8 + 2
    8-3+48 / 24
    53/24

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