f(x) = 2x+1, g(x) = x², h(x) = x+5. Nilai (fogoh) (-4) =

h(x) = x+5
h(-4) = -4+5
h(-4) = 1

g(x) = x^2
g(1) = 1^2
g(1) = 1

f(x) = 2x +1
f(1) = 2×1 + 1
f(1) = 2 + 1
f(1) = 3

(f○g○h)(-4) = (f(g(h(-4)))) = f(g(1)) = f(1) = 3

semoga mmbantu