Matematika

Pertanyaan

tentukan akar akar persamaan (x-3)² +2(x-3)-3=0

2 Jawaban

  • (x - 3)² + 2(x - 3) - 3 = 0
    x² - 6x + 9 + 2x - 6 - 3 = 0
    x² - 4x = 0
    x(x - 4) = 0
    x1 = 0 ; x2 = 4
  • (x - 3)² + 2(x - 3) - 3 = 0
    x² - 6x + 9 + 2x - 6 - 3 = 0
    x² - 4x = 0
    x(x - 4) = 0
    x = 0 V x = 4

    Hp = { 0,4 }

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