volume sebuah balok 1.800cm³ panjang = 15cm lebar = 6 cm . Tentukan a. tinggi balok b. Lp balok

Volume = panjang×lebar×tinggi
1800cm^3 = 15cm×6cm×t
1800cm^3 = 90cm^2 ×t
1800cm^3÷90cm^2 = t
20cm = tinggi
Tinggi = 20cm
Luas permukaan = 2(pl+pt+lt)
Luas = 2(15.6+15.20+20.6)
Luas = 2(90+300+120)
Luas = 2(510)
Luas 1020cm^2

v = p × l × t
1800 = 15 × 6 × t
1800 = 90 t
t = 1800 ÷ 90
t = 20 cm

Lp = 2 (pl + pt + lt)
Lp = 2 [(15 × 6) + (15 × 20) + (6 × 20)
Lp = 2 (90 + 300 + 120)
Lp = 2 (510)
Lp = 1020 cm^2