tuliskan simpangan baku dari data 4,8,5,9,10,6 tolong dibantu iya

langsung aja y

X = (4+8+5+9+10+6) / 6
X = 42/6 = 7

Sb = √(4-7)²+(8-7)²+(5-7)²+(9-7)²+(10-7)²+(6-7)² / 6

Sb = √ 9+1+4+4+9+1 / 6

Sb = √ 28/6

Sb = √ 14/3

semoga berguna +_+

rata2 : 4+8+5+9+10+6/6=7
s^2= 1/6 ((4-7)^2+(8-7)^2+(5-7)^2+(9-7)^2+(10-7)^2+(6-7)^2)
= 1/6 (9+1+4+4+9+1)
=1/6× 28
=14/3
maka simpangan baku= akar s^2= akar 14/3