jika 2logp^6 - 2logq^2 = 8 dan 2logp + 2logq = 12 maka qlogp?
Matematika
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Pertanyaan
jika 2logp^6 - 2logq^2 = 8 dan 2logp + 2logq = 12 maka qlogp?
1 Jawaban
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1. Jawaban bapakdr
²log p^6 - ²log q^2 = 8
²log (p^6/q^2) = 8
²log (p^3/q)² = 8
2.²log (p^3/q) = 8
²log (p^3/q) = 8/2
²log (p^3/q) = 4
2⁴ = p^3/q
p^3/q = 2⁴
q = 2⁴/p³
²log p + ²log q = 12
²log p.q = 12
p.q = 2^12
p.(2⁴/p³) = 2^12
p/p³ = 2^12/2⁴
1/p² = 2^8
p² = 1/2^8
p = 1/2⁴
p = 2^-4
p.q = 2^12
2^-4.q = 2^12
q = 2^12 / 2^-4
q = 2^16
qlog p = 2^16log 2^-4 = -4/16 ²log 2 = -1/4