Matematika

Pertanyaan

jika 2logp^6 - 2logq^2 = 8 dan 2logp + 2logq = 12 maka qlogp?

1 Jawaban

  • ²log p^6 - ²log q^2 = 8
    ²log (p^6/q^2) = 8
    ²log (p^3/q)² = 8
    2.²log (p^3/q) = 8
    ²log (p^3/q) = 8/2
    ²log (p^3/q) = 4
    2⁴ = p^3/q
    p^3/q = 2⁴
    q = 2⁴/p³
    ²log p + ²log q = 12
    ²log p.q = 12
    p.q = 2^12
    p.(2⁴/p³) = 2^12
    p/p³ = 2^12/2⁴
    1/p² = 2^8
    p² = 1/2^8
    p = 1/2⁴
    p = 2^-4
    p.q = 2^12
    2^-4.q = 2^12
    q = 2^12 / 2^-4
    q = 2^16
    qlog p = 2^16log 2^-4 = -4/16 ²log 2 = -1/4

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