tolong bantu saya menjawab soal itu

LImit

a.lim(x->4) 10x²-8  -->  10(4)² -8 = 152

b. lim(x->1) (3x²)/(x² +x - 2) --> 3(1)² / ( 1²+1-2) = 3/0 = ∞

c. lim(x->1) (x² + x - 2)/(3x²) = (1² +1- 2)/(3(1²)= 0/3 = 0

d. lim(x->4) (x² - 4x)/(x²-2x8)
= lim (x->4) (x-4)(x) / (x-4)(x + 2)
= lim(x->4) x/(x+2)
= 4/(4+2) = 4/6 = 2/3

e. lim(x->∞) ( -2x⁴ - 3x²  + 7x)/(4x⁴ + 5x²-8)
bagi masing -masing dengan x⁴
limt (x->∞)  (-2 - 3(0) + 7(0)) / (4 + 5(0) -8(0))
= - 2/4
= - 1/2