Minto tolong di jawab yaaa

Gradien n = b/a = 2/(3)
syarat tegak lurus Mn × Mm = -1
Mm = -3/2
persamaan garis
y - (-2) = m (x-1)
y+2 = -3/2× ( x - 1)
kedua ruas dikali 2
2y + 4 = -3×(x-1)
2y = -3x + 3 - 4
2y = -3x - 1
2y + 3x + 1 = 0