Tentukan nilainya. Limit mendekati phi / 4 , sin ((phi/4) - x) tan (x- (phi/4)). (a) 2 (b) 1 (c) 0 (d) -1 (e) -2

[tex]\displaystyle \lim_{x\to\frac14\pi}\sin(\frac14\pi-x)\tan(x-\frac14\pi)=\sin(\frac14\pi-\frac14\pi)\tan(\frac14\pi-\frac14\pi)\\\lim_{x\to\frac14\pi}\sin(\frac14\pi-x)\tan(x-\frac14\pi)=\sin0\tan0\\\boxed{\boxed{\lim_{x\to\frac14\pi}\sin(\frac14\pi-x)\tan(x-\frac14\pi)=0}}[/tex]