tolong kerjakan pakai cara. makasih

1/Rp = 1/R2 + 1/R3
1/Rp = 1/8 + 1/8
1/Rp = 2/8
Rp = 8/2 = 4 ohm

R total = R1 + Rp = 6 + 4 = 10 ohm

Jadi, tegangan listrik (V) =
V = I.R
V = 3,6 × 10 = 36 volt (C)

R1=6Ω
R2=8Ω
R3=8Ω
I=3,6A
V=?
R2 dan R3 paralel
Rp=>[tex] \frac{1}{Rp} = \frac{1}{R2} + \frac{1}{R3} [/tex]
[tex] \frac{1}{Rp} = \frac{1}{8} + \frac{1}{8} [/tex]
[tex] \frac{1}{Rp}= \frac{1+1}{8} [/tex]
[tex] \frac{1}{Rp} = \frac{2}{8} [/tex]
[tex] \frac{Rp}{1} = \frac{8}{2} [/tex]
Rp=4Ω
sedangkan R1 sama Rp jadi seri
Rs=R1+Rp
Rs=6+4
Rs=10Ω=Rt

rumus mencari V
V=IxR
V=3,6x10
V=36v
dan jawabannya C