Matematika

Pertanyaan

diketahui fungsi g(x)= 3x+11 dan (g o f) (x) = 3x2 - 6x + 8. nilai dari f(3)

2 Jawaban

  • (gof)(x) = 3x² - 6x + 8
    g(f(x) = 3x² - 6x + 8
    3(f(x) + 11 = 3x² - 6x + 8
    3(f(x) = 3x² - 6x + 8 - 11
    3(f(x) = 3x² - 6x - 3
    f(x) = (3x² - 6x - 3)/3
    f(x) = x² - 2x - 1

    f(3) = 3² - 2(3) - 1
    f(3) = 9 - 6 - 1
    f(3) = 2
  • mencari f(x)
    (g o f)(x) = 3x² - 6x + 8
    g(f(x)) = 3x² - 6x + 8
    3(f(x)) + 11 = 3x² - 6x + 8
    3(f(x)) = 3x² - 6x + 8 - 11
    3(f(x)) = 3x² - 6x - 3
    f(x) = (3x² - 6x - 3) / 3
    f(x) = x² - 2x - 1

    mencari nilai f(3)
    f(x) = x² - 2x - 1
    f(3) = (3)² - 2(3) - 1
    f(3) = 9 - 6 - 1
    f(3) = 2

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