nilai dari lim (2x-5-√4x²-10x+5)

[(2x - 5) - √4x² - 10x + 5)]
= (√(2x - 5)² - √4x² - 10x + 5)
= (√4x² - 20x + 25 - √4x² - 10x + 5)

Lim √ax² + bx + c - √px² + qx + r)
= b - q / 2√a

= -20 - (-10) / 2√4
= -20 + 10 / 2 × 2
= -10/4
= -2,5